Speed. One car travels 12 mph faster than another. While one car travels 141 mi, the other travels 105 mi. How fast is each car
traveling?

the speeds of the cars are 47mph for the faster one, and 35mph for the slower one.

Step-by-step explanation:

Here you must remember the relation:

Speed = distance/time.

So we have car A and car B, with Sa the speed of car A, and Sb the speed of car B.

We know that:

Sa = Sb + 12mph.

and in the same time T, car A travels 141mi, while car B travels 105mi, then we have:

Sa*T = 141mi

Sb*t = 105mi

we can take the quotient of those two and get:

(Sa/Sb) = 141/105.

now we can replace Sa by Sa = Sb + 12mph.

(Sb + 12mph)/(Sb) = 141/105.

Sb + 12mph = (141/105)*Sb

Sb*(141/105 - 1) = 12mph

Sb = 12mph/(141/105 - 1) = 35mph.

and we know that:

Sa = Sb + 12mph = 35mph + 12mph = 47mph.

1 and 0

step-by-step explanation:

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