The y-intercept in the linear equation −2y−4x−6=0 is _[blank]_. will give brainliest

-3 is the value of the location where the line crosses the y-axis,and is commonly referred in the slope-intercept form of a line "the intercept". Now it may be your teacher expects you to answer this as the point on the plane where the y-intercept occurs, and that should be the point (0, -3). Make sure you follow your teacher's notation.

Step-by-step explanation:

Re-write the equation given in slope=intercept form by isolating the variable "y" on one side of the equation and expressing the rest in slope*x + y-intercet form:

which tells us that the slope of the line is -2 and it y-intercept is "-3".

Now, watch out because you may be asked to write the actual coordinates of the y-intercept, which are: (0, -3)

giving the x-coordinate 0 and the y-value where the line crosses the y-axis.

-3.

Step-by-step explanation:

-2y - 4x - 6 = 0

-2y = 4x + 6

y = -2x - 3

So, the y-intercept is (0, -3).

Hope this helps!

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation: