Marissa has a photograph that measures 2 in. by 4 in. She has mounted the picture on a mat so that there is a border that measures 1 in. around the picture. The graph shows a representation of the photograph and the mat on the coordinate grid. Marissa has decided to dilate the picture and the mat by a scale factor of 2. Draw the new image for the picture and mat on the coordinate grid.

The new size of the picture is and the new size of the mat is This is shown in attached images.

Given-

The size of the photograph is 2 by 4 in.

Marissa's photograph original size is 2 by 4 in. This is shown in the graph with image one.The boundary required for the mat is 1 in after the photograph applied. Thus the length of the mat must be 3 by 5 in. Refer Image two.When Marissa decided to  the picture by the scale factor two she need to multiply its dimension with two.

  Thus the new dimension of the Picture is,

         

         

Hence the new size for the picture is 4 by 8 in. This is shown in graph in image three.When Marissa decided to dilate the mat by the scale factor two she need to multiply its dimension with two.

        Thus the new dimension of the mat is,

       

       

Hence the new size for the mat is 6 by 10 in. This is shown in graph in image four.

Hence the new size of the picture is 4 by 8 and the new size of the mat is 6 by 10. This is shown in attached images.

For more about the scaling the graph follow the link below-

link

     

Step-by-step explanation:

The initial image of the photo is 2 in by 4 in.  The mat is 4 in by 6 in.

The new image is dilated by a scale of 2.  So we double the dimensions.  The new photo is 4 in by 8 in.  The new mat is 8 in by 12 in.

All except for b, because polynomial functions can be quadratic, cubic, witticisms and etc only non negative exponents of negative it is not a polynomial function

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