The length of a rectangle is increasing at a rate of 9 cm/s and its width is increasing at a rate of 3 cm/s. When the length is 7 cm and the width is 4 cm, how fast is the area of the rectangle increasing?

Given :

The length of a rectangle is increasing at a rate of 9 cm/s and its width is increasing at a rate of 3 cm/s.

When the length is 7 cm and the width is 4 cm .

To find :-

how fast is the area of the rectangle increasing?

Solution :-

As we know that :-

A = lb

To find the rate :-

d(A)/dt = d(lb)/dt .

Differenciate :-

dA/dt = l (db/dt ) + b (dl/dt )

Substitute :-

dA/dt = 9*4 + 7*3

dA/dt = 36 + 21 cm²/s

dA/dt = 57 cm²/s

step-by-step explanation:

do i do it on a graph?

step-by-step explanation: