Find the dimensions of a rectangle with perimeter 92 m whose area is as large as possible. (If both values are the same number, enter it into both blanks.) g

The dimension of the rectangle with perimeter 92 m whose area is as large as possible is 23m by 23m

If the perimeter of a rectangle is 92m, hence;

2(x+y) = 92

x is the length

y is the width

x + y = 46 1

If the area is as large as possible, hence;

xy = maximum 2

From equation 1, x = 46 - y

Substitute into the second equation

(46-y)y = P(y)

P(y) = 46y - y²

If the product is at the maximum, hence;

dP/dy = 46 - 2y = 0

46 - 2y = 0]

2y = 46

y = 23

Since x + y = 46

x = 46 - y

x = 46 - 23

x = 23

Hence the dimension of the rectangle with perimeter 92 m whose area is as large as possible is 23m by 23m

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The dimensions are x = 23 and y = 23

The maximum area of the rectangle  A = 529

Step-by-step explanation:

Step(i):-

Let given function area of the rectangle

                                    A = x y ....(i)

Given Perimeter of rectangle

                          2 ( x + y ) = 92

                               (x +y ) = 46

                                y = 46 - x ....(ii)

Substitute y = 46 - x in equation (i)

                             A = x (46 - x)

                            A = 46 x - x²  ....(iii)

Differentiating equation (iii) with respective to 'x'

                             ...(iv)

Step(ii):-

                       46 - 2 x = 0

                             46  = 2 x

                              x  = 23

Again Differentiating equation (iv) with respective to 'x'

The maximum value at x = 23

Step(iii):-

From(ii)

                      y = 46 - x

                     y   = 46 - 23

                   y    = 2 3

The dimensions are x = 23 and y = 23

Final answer :-

The dimensions are x = 23 and y = 23

The maximum area of the rectangle

                        A = x y

                      A = 23 ×23

                     A = 529

The maximum area of the rectangle  = 529

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5