The area of a rectangular garden is given by the quadratic function:A(x)=-6x^2+105x-294A . Knowing that the area, length, and width all must be a positive value puts restrictions on the value of x. What is the domain for the function? Explain how you determined the domain. For what value of x, produces the maximum area? What is the maximum area of the garden? What is the Range of the function? Explain how you determined the range? What value(s) of x produces an area of 100 square units?

Answer and Step-by-step explanation:

The domain of a function is the values the invariable can assume to result in a real value for the variable. In other words, it is all the values x can be.

Since it's related to area, the values of x has to be positive. The domain must be, then:

Solving the second degree equation:

x = 3.5 or x = 14

The domain of this function is 3.5 ≤ x ≤ 14

The maximum area is calculated by taking the first derivative of the function:

A'(x) = -12x + 105

-12x + 105 = 0

-12x = -105

x = 8.75

A(8.75) =

A(8.75) = 165.375

The maximum area of the garden is 165.375 square units.

The Range of a function is all the value the dependent variable can assume. So, the range of this function is: 0 ≤ y ≤ 165.375, since this value is the maximum it will reach.

A(x) = 100

Solving:

x = 5.45 or x = 12.05

The values of x that produces an area of 100 square units are 5.45 and 12.05

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.