With data from the 2009 National Health Interview Survey, the Centers for Disease Control estimated that 9.4% of U. S. children had asthma. Suppose that 12% of a random sample of 500 U. S. poor children have asthma. We used the estimate from the 2009 National Health Interview Survey to calculate a standard error of 0.013. The data allows the use of a normal model. So we can find an approximate 95% confidence interval for the percentage of all U. S. poor children who have asthma. Which interval is the approximate 95% confidence interval? Group of answer choices 0.094 to 0.146
0.107 to 0.133
0.026 to 0.214
0.068 to 0.12

And the best option would be:

0.094 to 0.146

Step-by-step explanation:

For this case we have the following info given:

represent the proportion estimated

represent the standard error

represent the confidence level

The confidence interval for the true proportion is given by:

And for 95% of confidence the critical value is and replacing we got:

And the best option would be:

0.094 to 0.146

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116