Pls help me with trig! i would rlly appreciate

c≤

Step-by-step explanation:

hypotenuse=√(a²+b²)=√(5²+6²)=√(25+36)=√61

cosθ=5/√61=5/√61× (√61/√61)=5√61/61

is ans

Step-by-step explanation:

given, a=5 and b=6

as the refrence angle is thit

p=6 and b= 5

therefore h

now cos thita =b/h

therefore cos thita=

...is ans..

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.