SOMEONE PLEASE HELP Solve 2 x - 1 < 7 and 5x + 3 < 3.

A. {x l x < 0}
B. {x l x < 4}
C. {x l 0 < x < 4}

Step-by-step explanation:

2x - 1 < 7

Add 1 to both sides

2x - 1 + 1 < 7+1

2x < 8

Divide both sides by 2

2x/2 < 8/2

x < 4

5x + 3 < 3

Subtract 3 form both sides

5x + 3 - 3 < 3-3

5x < 0

x < 0

x <4 & x < 0

So, solution ,

{x / x< 0 }

A. {x l x < 0}

Step-by-step explanation:

2 x - 1 < 7 and 5x + 3 < 3.

Solve one inequality at a time

2 x - 1 < 7

Add 1 to each side

2 x - 1+1 < 7 +1

2x <8

Divide by 2

2x/2 <8/4

x <4

Now solve the other

5x + 3 < 3

Subtract 3

5x +3-3 < 3-3

5x<0

x <0

Recombine

x<4 and x<0

We go with the more restrictive  and merge the overlapping interval since we have an and

x<0

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

it’s the first one your welcome