In a school of 685 students, there are 385 students involved in sports teams, and there are 450 involved with the music program. There are 87 students that are not involved in either
program. There are some students involved in both programs.
a) Draw a Venn diagram to represent this situation.
b) Use the additive principle of non-mutually exclusive sets to determine the number of
students that are involved in both team sports and music
C) use the addictive principle for the probability of non-mutually exclusive events to determine the probability of a student being involved in team sports or involved in music

A) check attached picture

B) 272

C) 0.4478

Step-by-step explanation:

From the information given ;

A) The Venn diagram of the information can be found in the attached picture.

B) Number of students involved in both team sports and music.

n(student in sports team) = 385

n(students involved in music) = 450

Number of students involved in both music and team sport = y

Number of students not involved in either team sport or music = 87

Total number of students = 650

Therefore,

n(music alone) = 450 - y

n(team sport alone) = 385 - y

Adding the following:

n(music alone) + n(team sport alone) + n( both music and team sport) + n(neither music nor team sport) = Total number of students

450 - y + 385 - y + y + 87 = 650

922 - y = 650

922 - 650 = y

y = 272

Therefore, number of students involved in both music and team sport = 272

C) probability of being involved in team sport or in music.

P(being involved in music) = (450 - 272) / 650 = 0.2738

P(being involved in team sport) = (385 - 272) / 650 = 0.1738

P(involved in both) = 272 / 650 = 0.4184

P(involved in neither) = 87 / 650 = 0.1338

P(being involved in team sport) or p(being involved in music)

P(being involved in team sport) + p(being involved in music)

0.1738 + 0.2738 = 0.4478

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer:   (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))