PLEASE HELP The areas of two similar triangles are 50 dm2, and 32 dm2. The sum of their perimeters is 117 dm. What is the perimeter of each of these triangles?

65 dm and 52 dm

Step-by-step explanation:

If the scale factor of the sides is k, then the scale factor of the areas is k^2.

The scale factor of the areas is (32 dm^2)/(50 dm^2) = 0.64 = k^2

The scale factor of the sides is k = \sqrt(0.64) = 0.8

The perimeters are in a ratio of 1:0.8

x + 0.8x = 117

1.8x = 117

x = 65

0.8x = 0.8(65) = 52

The perimeters are 65 dm and 52 dm.

can you put the picture up?

step-by-step explanation:

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}