Solve on the interval [0, 2pi):
1 + cos(theta) = (sqrt(3)+2)/2
a. pi/6 , 5pi/6
b....
Mathematics, 12.11.2019 15:31 keigleyhannah30
Solve on the interval [0, 2pi):
1 + cos(theta) = (sqrt(3)+2)/2
a. pi/6 , 5pi/6
b. pi/3 , 5pi/3
c. pi/6 , 11pi/6
d. 7pi/6, 11pi/6
Answers: 2
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