A sequence starts 1, 4, 9, 16 ... The nth term is n^2. Use this fact to find the nth term of the following sequences: a) 2, 5, 10, 17 b) 2, 8, 28, 32

n²+1

2n²

Step-by-step explanation:

We can see that 2, 5, 10, and 17 becomes 1, 4, 9, and 16 when we subtract 1.

So it adds 1. The nth will be n² + 1.

2, 8, 18, and 32 is the double of n². 1, 4, 9, and 16 are their half.

So the nth term becomes 2n².

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

the answer is 175.4379

step-by-step explanation: