A chemist needs 120 milliliters of a 33% solution but has only 13% and 73% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

40 ml of 73% solution required and 80 ml of 13% solution

Step-by-step explanation:

Let x = amt of 58% solution

It say's the amt of the resulting mixture is to be 120 ml, therefore

(120-x) = amt of 13% solution

A typical mixture equation

0.73x + 0.13(120-x) = 0.33(120)

0.73x + 15.6 - 0.13x = 39.6

0.6x=24

x=40 ml of 73% solution required

and

120 - 40 =80 ml of 13% solution

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step-by-step explanation:

a - base

b - exponent

so,