Which equation shows a valid step in solving /2x-6+2x+8 = 0? 2
2
o (f/2x-6)} = (/2x+8)
(°/2x-6 5)*- (- /2x+6
(1/2x-6) = (*/2x+6)
o (1/2x-6) = (-3/2x+6)
O
3

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

the radius is 2 times the diameter.

step-by-step explanation:

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated