In a church wing with 8 men and 10 women members find the probability that a 5 member committee chosen randomly will have a).all men.
b).3men and 2 women

a) Probability that a 5 member committee will have all men = 0.0065

b) probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

Step-by-step explanation:

Number of men = 8

Number of women = 10

Total number of members = 10 + 8 = 18

Probability = (Number of possible outcomes)/(Total number of outcomes)

Number of ways of selecting a 5 member committee from 18 people = = 8568 ways

a) Probability that a 5 member committee will have all men

Number of ways of selecting 5 men from 8 men

= = 56 ways

Probability that a 5 member committee will have all men = 56/8568

Probability that a 5 member committee will have all men = 0.0065

b)probability that a 5 member committee chosen randomly will have 3men and 2 women

Number of ways of selecting 3 men from 8 men

=   = 56 ways

Number of ways of selecting 2 women from 10 men

=   = 45 ways

Number of ways of selecting 3 men and 2 women = 56*45

Number of ways of selecting 3 men and 2 women = 2520

Probability of selecting 3 men and 2 women = 2520/8568 = 0.294

probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

step-by-step explanation: