Answer this please ?

a. x = 4

b. x = 17.5

Step-by-step explanation:

a. 5x/2 + 1 = 11

5x/2 = 10

5x = 20

x = 4

b. 2x/7 - 3 = 2

2x/7 = 5

2x = 35

x = 35/2

a) x = 4

b) x = 17.5

Step-by-step explanation:

a)

(5x)/2 + 1 = 11

(5x)/2 = 10

5x = 20

x = 4

b)

(2x)/7 - 3 = 2

(2x)/7 = 5

2x = 35

x = 17.5

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: