how many different three digit numbers can be formed using the digits 8, 5, 1, and 9 without repetition?

I was able to make 22

Step-by-step explanation:

The numbers are:

851

158

581

815

185

518

159

195

951

915

519

591

985

958

859

895

918

981

189

198

891

819

if the numbers are 8, 5, 1 and 9,

you could have

851, 859, 815, 819, 895, 891

518, 519, 581, 589, 591, 598

158, 159, 185, 189, 195, 198

915, 918, 951, 958, 985, 981

i dont know if these next ones will count-

5 x 8 x 9= 360

5 x 8 x 9 - 1 = 859

5 x 8 x 9 +1 = 361

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

10

step-by-step explanation: