Choose the best reason for using the median as the measure of central tendency. a. When you have a lot of fractions and decimals

b. When you want to find the average

c. When the sample size is large and includes outliers

d. When the sample size is large and does not include outliers

The median is usually preferred in these situations because the value of the mean can be distorted by the outliers. However, it will depend on how influential the outliers are. If they do not significantly distort the mean, using the mean as the measure of central tendency will usually be preferred.

When the sample size is large and includes outliers

Step-by-step explanation:

:)

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation