Find the domain and the range of the relation. Determine whether the relation is a function. StartSet left parenthesis negative 1 comma 0 right parenthesis comma left parenthesis 7 comma 0 right parenthesis comma left parenthesis negative 1 comma 9 right parenthesis comma left parenthesis negative 6 comma negative 9 right parenthesis EndSet{(−1,0),(7,0),(−1,9),(−6,−9)}

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

The relation is not a function.

Step-by-step explanation:

Given the relation: t{(−1,0),(7,0),(−1,9),(−6,−9)}

In the ordered pairs:

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

Next, we determine whether the relation is a function.

For a relation to be a function, each x must correspond with only one y value.

However, as is observed in the mapping attached below:

The x-value (-1) corresponds to two y-values (0 and 9)

Therefore, the relation is not a function.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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