What's the solution to system of equations
x + y=6
x= y + 2

x + y=6 1

x= y + 2 2

Substitute x= y + 2 into x + y=6

y + y + 2 = 6

2y = 6 - 2

2y = 4

Divide both sides by 2

y = 2

Substitute y = 2 into x + y=6

x + 2 = 6

x = 6 - 2

x = 4

y = 2 x = 4

hope this helps.

(4,2)

Step-by-step explanation:

x + y=6

x= y + 2

Substitute the second equation into the first

x+y = 6

(y+2) +y =6

Combine like terms

2y+2 = 6

Subtract 2

2y+2-2 = 6-2

2y = 4

Divide by 2

2y/2 = 4/2

y =2

Now find x

x = y+2

x = 2+2

x=4

(4,2)

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

i think it would be c

mark brainliest if im right

step-by-step explanation: