1. The graph F(x)= 3^x, left 2 units, and down 3. 2. The graph f(x)= 1^x/2 translated down 2 units. 3. the graph of f(x)=4^x, stretched horizontally by a factor of 3 4. The graph of f(x)=2^x up 4 units and right 3 units. Write the function of each. Thank you

1.) F(x) = 3^(x+2) - 3

2.) F(x) = 1^x/2 - 2

3.) F(x) = 4^(1/3x)

4.) F(x) = 2^(x - 3) + 4

Step-by-step explanation:

 1.) The graph F(x)= 3^x, left 2 units, and down 3. This is a translation. The translated function will be

F(x) = 3^(x+2) - 3

Note: for x - axis, left is positive while right is negative

2.) The graph f(x)= 1^x/2 translated down 2 units. The translated function will be

F(x) = 1^x/2 - 2

3.) the graph of f(x)=4^x, stretched horizontally by a factor of 3.

That is, it is stretched along the x - axis.

X will be multiply by 1/3. The stretched function will therefore be

F(x) = 4^(1/3x)

4.) The graph of f(x)=2^x up 4 units and right 3 units. --

The translated function will be

F(x) = 2^(x - 3) + 4

d

step-by-step explanation:

d

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: