Pls help from number five 5

P = 40 cm

A = 51 cm^2

Step-by-step explanation:

Perimeter: Add the lengths of all sides. The sides whose length are not shown can be calculated by subtraction.

perimeter = 3 cm + 12 cm + 8 cm + 3 cm + (8 cm - 3 cm) + (12 cm - 3 cm) =

= 3 cm + 12 cm + 8 cm + 3 cm + 5 cm + 9 cm

= 40 cm

Area:

You can find the area by calculating the sides of smaller rectangles and adding the areas. You can also calculate the area by thinking of a large rectangle from which a smaller rectangle inside was removed. I'll use the second method.

area of larger rectangle = 12 cm * 8 cm = 96 cm^2

area of removed rectangle = (8 cm - 3 cm) * (12 cm - 3 cm) = 5 cm * 9 cm = 45 cm^2

shaded area = 96 cm^2 - 45 cm^2 = 51 cm^2

to rewrite a literal equation you may need to divide by a number, or by a variable.

hope i .

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.