Three hunters X, Y and Z aim at a bird on top of a tree. Their individual probabilities of killing the bird are 3/5, 2/3 and 5/6 respectively. Find the probability that

i. Only X and Y kill the bird

ii. Only two of them kill the bird

iii. Only Z kill the bird

iv. Only one of them kill the bird

v. None of them kill the bird

vi. All of them kill the bird

i. Only X and Y kill the bird = 2/5

ii. Only two of them kill the bird= 0.11

iii. Only Z kill the bird= 5/6

iv. Only one of them kill the bird= 1/3

v. None of them kill the bird= 0

vi. All of them kill the bird= 1

Step-by-step explanation:

Probability of x= 3/5

Probability of y = 2/3

Probability of z = 5/6

i. Only X and Y kill the bird

= 3/5 * 2/3

= 2/5

ii. Only two of them kill the bird

=Either x and y or x and z or y and z

= 2/5 or 1/2 or 5/9

= 0.111

iii. Only Z kill the bird

= 5/6

iv. Only one of them kill the bird

= 3/5 or 2/3 or 5/6

= 1/3

v. None of them kill the bird

0

vi. All of them kill the bird

1

idk

step-by-step explanation:

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8