Three no. s are in the ratio 1:2:3 the sum of their cube is 7776 find the numbers

6,12,18

Step-by-step explanation:

write the question as an equation

(1x)^3 + (2x)^3 + (3x)^3 = 7776

Simplify, rearrange and solve.

1x^3 +8x^3 + 27x^3 = 7776

36x^3 = 7776

x^3 = 216

x = 6.

Now, the numbers were= x, 2x, 3x = 6,12,18

Hope this helps

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3