I need help with this

112 degrees.

Step-by-step explanation:

So, we are given that one of the angles is equal to 124 degrees.

Using that, we can find out what angle KN. 180 minus 124 is 56.

Alright, we found one of the interior angles of the triangle.

We can actually find the measure of another angle.

JKN is congruent to NOL. So if JKN is 124, then NOL is 124.

We can find the other interior angle of the triangle.

180 minus 124 is also 56.

So this triangle is actually an isosceles, acute triangle.

We can actually find the third interior angle.

We know that the sum of all angles in a triangle is equal 180 degrees.

So, add up 56 plus 56 which 112.

You are left with 112 plus x =180.

Subtract 112 from both sides to isolate x.

Now, you are left with 68 degrees.

Go back to that third interior angle (x=68 degrees).

The exterior angle to the right of the triangle can form supplementary angles with the third interior angle.

We know supplementary angles also add up to 180.

So, 68 plus x=180

Subtract 68 from both sides.

You get x=112.

This is the the size of angle OLM.

This makes sense because OLM is twice as large as PON which is 56. Multiplying 56 times 2 and that gets you 112.

Hope this helps!

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step-by-step explanation:

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