Mathematics, 02.07.2020 14:01 lyricbrown9055

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes n1

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Answer from: emj70

The proportion in a t-distribution less than -1.4 is 0.095 and this can be determined by using the given data.

Given :

Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means.The samples have sizes $\rm n_1$ = 12 and $\rm n_2$ = 12.T statistics = -1.4

The degree of freedom is given by:

$\rm df=Min.(n_1-1,n_2-1)$

$\rm df=Min.(12-1,12-1)$

df = Min.(11 , 11)

df = 11

Now, compute the proportion in t-distribution:

$\rm P(t_{df}$

$\rm = P(t_{11}1.4)$

= 0.095

The proportion in a t-distribution less than -1.4 is 0.095 and this can be determined by using the given data.

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Use a t-distribution to answer this question. Assume the samples are random samples from distributio

Answer from: alailatrenee18541

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

$n_{1}=n_{2}=12\\t-stat=-1.4$

Compute the degrees of freedom as follows:

$\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)$

$=\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11$

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

$P(t_{df}$

$=P(t_{11}1.4)\\\\=0.095$

*Use a t-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

Answer from: Quest

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?