Sally was asked to find two integers such that one is three less than 4 times the other and the sum of the two integers is 42. the integers must be
a. 14, 28
b. 15, 27
c. 9, 33
d. -13, 55

To solve this problem, we are going to set up a system of equations, letting x represent the value of one integer and y the value of the other.

x = 4y - 3

x + y = 42

To solve this system of equations, we are going to use substitution.  We know that x = 4y - 3, so we are going to replace the variable x with this value in the second equation.

(4y - 3) + y = 42

Now, let's combine like terms in the equation.

5y - 3 = 42

Next, let's add 3 to both sides of the equation to get the variable y alone.

5y = 45

Finally, let's divide both sides by 5.

y = 9 

Now that we know the value of y, let's substitute this value back into the second equation.

x + (9) = 42

Let's subtract 9 from both sides of the equation to get the variable x alone.

x = 33

Thus, the answer to your question is C. 9, 33 because y = 9 and x = 33 in our equations.

Hope this helps! :)

35=5×77=7×1when we simplify 7 by 7we will get 5 and 1, 5 divided by 1 is 5