Rectangle J′K′L′M′ shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV. What will be the location of T′ in the image trapezoid S′T′U′V′? (18, −2) (18, 2) (15, −2) (15, 2)

(18,2)

Step-by-step explanation:

Let's start by determining the transformation of Rectangle J′K′L′M′

We can look at L.

In the original rectangle, L is at (-4,-2)

In the transformation, L' is at (9,-5)

|-4-9|=|-13|=13

|-2-(-5)|=|-2+5|=3

So the transformation is 13 units right and 3 units down.

In trapezoid STUV, the coordinates of T are are (5,5)

We need to move it 13 units left and 3 units down.

This means we add 13 to the x coordinate and subtract 3 from the y coordinate.

5+13=18

5-3=2

The location of T' will be (18,2)

(18, 2)

Step-by-step explanation:

As per the graph, we can see the transformation of 13 points right and 3 points down.

Point T on the trapezoid has coordinate of (5, 5)

After same transformation its coordinates will be T'= (5+13, 5-3)= (18, 2)

Correct choice is second one from the top.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

step-by-step explanation: