Find an equation of the tangent line to the curve at the given point.
y = sec x, (π/6, 2√3/3)

The question is asking to calculate the said equation of the tangent line to the curve at the given point and base on my further research and further understanding about the said equation, I would say that the answer would be letter y=(2/3)x+(2/√3−π/9). I hope you are satisfied with my answer and feel free to ask for more 

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