The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weighs 123 pounds when she is at sea level, 3960 miles from the center of Earth, how much will she weigh when she is at the top of a mountain, 3.2 miles above sea level?

Her weight is approximately 122.8lb

Step-by-step explanation:

Given

Inverse proportion;

Weight = 123lb when distance = 3960 miles from center of earth

Required

Calculate the weight when distance is 3.2 miles above sea level

Let weight be represented by W and distance by D

From the question, we understand that;

Weight is inversely proportional to square of distance;

Mathematically; this is

Convert proportion to equation

Where k is the constant of  proportionality

When W = 123; D = 3960.

This implies that

Make k the subject of formula

Calculating her weight when she's at the top of mountain, 3.2 miles above sea level

First, her distance from center of earth has to be calculated

Distance = Previous distance + 3.2

Distance = 3960 + 3.2

Distance = 3963.2

Now, her weight can be calculated using

Substitute for k and D

5x+10 is the correct one

hope this

the above table 1 will calculate the population size (n) after a certain length of time (t). all you need to do is plug in the initial population number (no), the growth rate (r) and the length of time (t). the constant (e) is already entered into the equation. it stands for the base of the natural logarithms (approximately 2.71828). growth rate (r) and time (t) must be expressed in the same unit of time, such as years, days, hours or minutes. for humans, population growth rate is based on one year. if a population of people grew from 1000 to 1040 in one year, then the percent increase or annual growth rate is 40/1000 x 100 = 4 percent.

step-by-step explanation: