Given: BC ⊥ CA , Prove: m∠A+m∠B=90°

With points A, B and C a right triangle is formed.

Given that BC ⊥ CA, then m∠C = 90°.

The addition of the angles of a triangle is equal to 180°, therefore:

m∠A + m∠B + m∠C = 180°

Substituting with m∠C = 90°:

m∠A + m∠B + 90° = 180°

m∠A + m∠B = 180° - 90°

m∠A + m∠B = 90°

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.