The certain article reported that, in a study of a particular wafer inspection process, 150 dies were examined by an inspection probe and 85 of these passed the probe. Assuming a stable process, calculate a 95% confidence interval for the proportion of all dies that pass the probe.

95% of confidence intervals for the proportion of all dies that pass the probe.

(0.4867 , 0.6453)

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 150

The sample proportion

Level of significance = 0.05

The critical value Z₀.₀₅ = 1.96

Step(ii):-

95% of confidence intervals for the proportion of all dies that pass the probe.

( 0.566 - 0.0793 , 0.566 + 0.0793)

(0.4867 , 0.6453)

Conclusion:-

95% of confidence intervals for the proportion of all dies that pass the probe.

(0.4867 , 0.6453)

a) justify

step-by-step explanation:

justifying is just part of everyday life. justify kind of means proof so i think the answer is a) justify.

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step-by-step explanation: