A fish jumps out of water. The function y = −16t 2 + 11t models the height, in feet, of the fish above water after t seconds. A) How long is the fish out of water? B) What is the maximum height of the fish above the water?

A) The fish was out of water for 0.6875 seconds.

B) Maximum height = 5.672

Step-by-step explanation:

Height is modeled by;

y = -16t² + 11t

A) To find total time of the fish out of water, we need to find the x - intercept. That is the points where y = 0

So, 0 = -16t² + 11t

So the roots of this equation are;

t = 0 or 0.6875

Thus,the fish was out of water for 0.6875 seconds.

B) y = -16t² + 11t

The x coordinate of the vertex is at - b/2a

For y = -16t² + 11t

a = -16, b = 11, c = 0

So, -b/2a = -11/(2*-16) = 11/32

The maximum height will be at the y-coordinate of the vertex.

Thus, we need to find f(11/32)

f(11/32) = -16(11/32)² + 11(11/32) = 1.890625 + 3.78125 = 5.671875 ≈ 5.672

3=log(n)=2

answer a: product property

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb