What is the distance between (6, -2) and (1, -2)

5 units.

Step-by-step explanation:

For:

(X1, Y1) = (6, -2)

(X2, Y2) = (1, -2)

d=√(1−6)²+(−2−(−2))²

d=√(−5)²+(0)²

d=√25+0

d=√25

d=5

Hope this helped!

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.