Work out the perimeter of the triangle when the sides are : 3x-5 2x 19-x

4x + 14

Step-by-step explanation:

The perimeter of the triangle is equal to the sum of its three sides.

The sides of the triangle are 3x-5, 2x, and 19-x.

Calculate their sum.

3x - 5 + 2x + 19 - x

Rearrange.

3x + 2x - x + 19 - 5

Add or subtract like terms.

4x + 14

The perimeter of the triangle is 4x + 14.

The perimeter of the triangle is 4x+14

Step-by-step explanation:

Perimeter is sum of all sides.

So,

=> 3x-5+2x+19-x

=> 5x-x-5+19

=> 4x+14

So, The perimeter of the triangle is 4x+14

answer: i believe its b. if you sound out the sentences that sounds wrong.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°