Simplify this expression. (2/x-y) + (3/x+y) - (5/y+x) - (7x-9y/y^2-x^2) = _/ y^2 - x^2

(5y-17x)/ (y^2-x^2)

Step-by-step explanation:

(2/x-y) + (3/x+y) - (5/y-x) - (7x-9y/y^2-x^2) =

Get a common denominator of y^2 - x^2

2/ (x-y) = -2 /( y-x) * (y+x)/(y+x)  = (-2y -2x) / (y^2 -x^2)

(3/x+y) = 3/ (x+y) * (y-x)/(y-x) = (3y-3x) /  (y^2 -x^2)

-5/(y-x) = -5/(y-x) *(y+x)/(y+x) = -5y-5x /  (y^2 -x^2)

- (7x-9y/(y^2-x^2) = -7x +9y/ (y^2-x^2)

Combine the numerators since the denominators are equal

-2y -2x +3y-3x-5y-5x-7x+9y

5y-17x

Put this over the denominator

(5y-17x)/ (y^2-x^2)

Solution,

hope this helps...

Good luck on your assignment...

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

∠cbe and ∠deb are same-side interior angles.

i took the test