If 0 < z ≤ 90 and sin(9z − 1) = cos(6z + 1), what is the value of z? z = 3 z = 4 z = 5 z = 6

z = 6

Step-by-step explanation:

sin (9z - 1) = cos (6z + 1)

90 - (9z - 1) = 6z + 1

90 - 9z + 1 = 6z + 1

9z + 6z = 90

15z = 90

z = 6

I Hope I've helped you.

thats one

step-by-step explanation:

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step-by-step explanation:

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