Mathematics, 01.07.2020 15:01 dhurtado1195

Derive the equation of the parabola with a focus at (−7, 5) and a directrix of y = −11. f(x) = one thirty second(x + 7)2 − 3
f(x) = −one thirty second(x + 7)2 − 3
f(x) = −one thirty second(x − 7)2 − 3
f(x) = one thirty second(x − 7)2 − 3

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Derive the equation of the parabola with a focus at (−7, 5) and a directrix of y = −11. f(x) = one thirty second(x + 7)2 − 3 f(x) = −one thirty second(x + 7)2 − 3 f(x) = −one thirty second(x − 7)2 − 3 f(x) = one thirty second(x − 7)2 − 3

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Derive the equation of the parabola with a focus at (−7, 5) and a directrix of y = −11. f(x) = one thirty second(x + 7)2 − 3
f(x) = −one thirty second(x + 7)2 − 3
f(x) = −one thirty second(x − 7)2 − 3
f(x) = one thirty second(x − 7)2 − 3