o get from his house to the lecture hall at school, Lin walked west 651 feet. After class, he walked northeast 910 feet to the gym. Finally, he walked 615 feet back to his house from the gym. A triangle has points gym, Lin apostrophe s house, and lecture hall. The distance between the lecture hall and gym is 910 feet. The distance between the gym and Lin apostrophe s house is 615 feet. The distance between the lecture hall and Lin apostrophe s house is 651 feet. What general direction did Lin walk from the gym to his house, and what type of triangle did his walking path form? Lin walked south, creating a right triangle. Lin walked southwest, creating an obtuse triangle. Lin walked southeast, creating an acute triangle. Lin walked directly east, creating a right triangle.

Lin walked southwest, creating an obtuse triangle.

Step-by-step explanation:

The triangle has sides of lengths 651 ft, 615 ft, and 910 ft.

If this were a right triangle, then the Pythagorean theorem would have to work. If tis were a right triangle, the the two shorter sides would be the legs forming the right angle.

a^2 + b^2 = c^2

615^2 + 651^2 = 378225 + 432801 = 802026

sqrt(802026) = 896

Since the calculation of the length of the hypotenuse for a right angle is 896 ft, but the actual third side is 910 feet, then this is not a right triangle. In addition, in order to accommodate a longer third side, you'd have to open up the angle a bit making it an obtuse angle. This is an obtuse triangle.

Lin walked southwest, creating an obtuse triangle.

q1 a person or thing situated away or detached from the main body or system. a cluster is a a mash of many things.

q2 do

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841