Write a quadratic equation with the solutions x=-5+sqrt 13/2 , -5-sqrt 13 /2 HELP please

If we used the quadratic formula to solve the equation we can say:

-b = -5

b² - 4ac = 13

2a = 2

Solving the first and last equations we get b = 5 and a = 1. Substituting these values into the second equation we get:

25 - 4c = 13

Solving this we get c = 3 so the answer is x² + 5x + 3.

a = 11 : 4

b = 38

c = 1 for every 6

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1