triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R If ∠P measures 27°, ∠R measures 135°, and p equals 9.5, then which length can be found using the Law of Sines? p r RQ PR

side r

Step-by-step explanation:

Using the Law of Sines in Δ PQR, that is

= =

Given ∠ P, ∠ R and p then side r can be found

= , substitute values

= ( cross- multiply )

r sin27° = 9.5 sin135° ( divide both sides by sin27° )

r = ≈ 14.8 ( to 1 dec. place

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus

there are no choices to this, can you give us some choices so that i can answer it

step-by-step explanation: