Someone pliss answere this for me

1) ∠AEB ≈ 83.7°

2) CE  = 6.1 cm

3) BC ≈ 7.1 cm

Step-by-step explanation:

1) Use theorem of cosine

c² = a² + b² - 2ab*cos(α)

4.5² = 3² + 3.7² - 2*3*3.7 *cos(∠AEB)

cos(∠AEB) = (4.5² - 3² - 3.7²) /(- 2*3*3.7) = 0.11

∠AEB = arc cos(∠AEB) = arc cos(0.11) ≈ 83.7°

2)

∠CED =∠AEB = 83.7° as vertical angles

Use law of sine

CD/sin(∠CED) = CE/ sin(∠CDE)

7/sin(83.7) = CE/sin(60°)

CE = 7*sin(60°)/sin(83.7°) = 6.1 cm

3.

∠BEC + ∠CED = 180°

∠BEC = 180° - ∠CED = 180° - 83.7° = 96.3°

Use theorem of cosine

c² = a² + b² - 2ab*cos(α)

BC² = BE² + CE² - 2 BE * EC *cos(∠BEC)

BC² = 3² + 6.1² - 2*3 * 6.1 *cos(96.3°) ≈ 50.23 cm

BC = √(50.23)≈ 7.1 cm

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°