Tia used a photocopier to dilate the design for a monorail track system. The figure shows the design and its photocopy: Two irregular quadrilaterals ABCD and EFGH are drawn. EFGH is the photocopy of design ABCD. AB measures 17 meters, BC measures 14 meters. No dimensions on EFGH are shown. The ratio of DA:HE is 1:2. What is the length, in meters, of side FG on the photocopied image?

FG = 28 meters

Step-by-step Explanation:

==>A design ABCD and its dilated photocopy EFGH.

Length of side AB = 17m

BC = 14m

DA:HE = 1:2

==>Required:

Length of side FG on the photocopy EFGH, in meters.

==>Solution:

Dilation of design ABCD would, upon transformation would produce a photocopy EFGH that is similar. Thus, ABCD ~ EFGH

Since ABCD is similar to EFGH, it means the ratio of their corresponding sides would be the same, and also have the same scale factor.

Therefore, it means DA:HE = BC:FG

Therefore, let's find length of side FG of the photocopy using the ratio1:2 that is given for DA:HE, which would also apply as the scale factor or ratio for all other corresponding sides.

Thus,

1:2 = BC:FG

1:2 = 14:FG

1/2 = 14/FG

Cross multiply to solve for FG

1×FG = 14×2

FG = 28 meters

glide reflection.

its mainly because the pattern will be infinite and will never end. it will look like a gilder or like a filpbook when set to motion.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm