The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line?

y+13 = 5(x+2)

Step-by-step explanation:

The point-gradient (or point-slope) formula is y−y1=m(x−x1)

Sub the points into the equation

y - -13 = 5(x--2)

y+13 = 5(x+2)

Therefore the point-gradient formula of the line is y+13 = 5(x+2)

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