Consider the density curve below. 0.25

х

1

2

3

4

5

Find the percent of the area under the density curve where x is less than 4.

Check Explanation.

Step-by-step explanation:

Although, the density curve for this question is missing and isn't available online, I would use an example of another density curve to explain how this could be easily done.

From the density curve attached to this question, the total area under the curve is the are of the triangular shape formed by this curve with the x-axis.

Total Area under the curve = ½×base×height

= ½ × (5-1) × 0.5 = 1 square unit

Area under the density curve where x is less than 4 is a trapezium.

Area of a trapezium = ½ (a+b) h

For the area under the density curve where x is less than 4,

a = 0.5, b = (0.5/4) = 0.125, h = (4-1) = 3

Area under the density curve where x is less than 4 = ½ (0.5+0.125) × 3 = 0.9375 square unit

In terms of the total area, Area under the density curve where x is less than 4 covers

(0.9375/1) × 100% = 93.75%

Hope this Helps!!!

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°