The picture shows a triangular island: Which expression shows the value of q? r cos 55°
r sin 55°
s/sin55°
s/cos55°

In trigonometric ratios, the cos (x) = adjacent over hypotenuse.

Therefore, in the diagram,  cos (55°) = s/q

To isolate q, divide both sides by s

cos (55°) / s = 1/ q

Then flip both numerators and denominators (raise both sides to the power of -1)

q = s / cos (55°)

S/cos 55

Step-by-step explanation:

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine