201 = 11

40523 = 13

24680975012 = 432

101804102 = ?

Question: Find the value for x

201 = 11

40523 = 13

24680975012 = 432

101804102 = x

After quite some time, I think there is too little to go on.

So based on these numbers alone, one single reliable answer can not be given.

Step-by-step explanation:

We need to find x.

Clearly some form of exponential growth is happening, because the numbers can not get that big by just adding or multiplying.

To find the exponent, you need to use the root function on your calculator. The standard root is based on ground number 2, so you need another ground number to be able to find the propper exponent.

IN GENERAL:

IN GENERAL:root( x, y ) = z

IN GENERAL:root( x, y ) = zz^x = y

root(11, 201) =1.61950189218624

so 1.61950189218624^11= 201

Try to predict the next number by a "formula". (There is no telling if this "formula" holds up in any other cases, but it seems to be working here at least):

y^2 + x^2 + 1 = next number (for xnew = xold +2)

201^2 + 11^2 + 1 =40523

xnew = xold +2 and xold was 11, so xnew = 11 + 2 = 13

root(13,40523) = 2.26171867395748

2.26171867395748^13 = 40523

Trying to predict the next number by the formula does not work:

Trying to predict the next number by the formula does not work:40523^2 + 13^2 + 1 = 1642113699

Trying to predict the next number by the formula does not work:40523^2 + 13^2 + 1 = 1642113699Since 1642113699^2 is way too big for any following number, the conclusion must be: this seems to be a dead end.

root(x,101804102) = z

z^x = 101804102

Try to predict the next number by applying what we do know in our "formula" (which is unreliable to begin with...).

y^2 + x^2 + 1 = next number (for xnew = xold +2)

101804102^2 + (x+2)^2 + 1 = 24680975012

101804102^2 + (x+2)^2 + 1 = 24680975012

root(432,24680975012) = 1.0569547485616

1.0569547485616^432 = 24680975012

After quite some time, I think there is too little to go on.

So based on these numbers alone, one single reliable answer can not be given.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

answer is  

a.

p = 78

step-by-step explanation: