The number of clients arriving at a bank machine is Poisson distributed with an average of 2 per minute. What is the probability that no more than 2 customers will arrive in a minute

The probability that no more than '2' customers will arrive in minute = 1.5412

Step-by-step explanation:

Explanation:-

Mean of the Poisson distribution 'λ' = 2 per minute

P(X=x) = e⁻ˣ λˣ/x!

The probability that no more than '2' customers will arrive in minute

P(x≤ 2) = P(x=0) +P(x=1)+P(x=2)

           = e⁻² (2)°/0! + e⁻²(2)¹/1!+e⁻² (2)²/2!

          = 1 + 0.2706 + 0.2706

          = 1.5412

The probability that no more than '2' customers will arrive in minute = 1.5412

i think the answer is b.

step-by-step explanation:

not 100% sure though.

1/2*qr*rs

step-by-step explanation: