What is the domain of f(x)= 3squareroot x?

 Domain: x ≥ 0    Interval Notation: x = [0, ∞)

Step-by-step explanation:

f(x) = 3√x

There IS a restriction on x because it is inside the square root symbol.

In order for the radical to be a real number, the expression under the radical must be greater than or equal to 0. The value inside the radical is "x".

So, x ≥ 0       It is already solved for x so no further work is needed.